200 mL of decimolar H2SO4 is mixed with 200 ml of semimolar NaOH, find the total MV.

The formula use will be:  M_H2SO4V_H2SO4 + M_NaOHV_NaOH = M_finalV_final

 The no. of moles of 0.1 M sulphuric acid or M_H2SO4V_H2SO4 = 0.1 M x 0.2 l = 0.02 moles

 The no. of moles of 0.5 M NaOH or M_NaOHV_NaOH = 0.5 M x 0.2 l = 0.1 moles

 So, the total no. of moles or one can say M_finalV_final = 0.02 + 0.1 = 0.12 moles

 The final volume = 0.2 litres + 0.2 litres = 0.4 litres

 So, the molarity of mixture obtained after mixing = total no. of moles/total volume

           

                                                                         = 0.12/0.4

                                                                     

                                                                         = 0.3 M