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ICSE Class 9 Answered

11(x-5)+10(y-2)+54=0 7(2x-1) +9(3y-1)=25 Elimination method
Asked by krcraju1973 | 28 Jun, 2019, 11:40: AM
answered-by-expert Expert Answer

11(x - 5)+10(y - 2) + 54 = 0

7(2x - 1) +9(3y - 1) = 25

11x - 55 + 10y - 20 + 54 = 0

11x + 10y = 21 ....(i)

7(2x - 1) +9(3y - 1) = 25

14x - 7 + 27y - 9 = 25

14x + 27y = 41 ....(ii)

Hence,

11x + 10y = 21 ....(i)

14x + 27y = 41 ....(ii)

Multiplying by 14 to (i) and multiplying by 11 to (ii) we get

154x + 140y = 294 ....(iii)

154x + 297y = 451 ...(iv)

Subtracting (iii) from (iv) we get

157y = 157

y = 1 and put it in (i) we get x = 1 

Answered by Sneha shidid | 28 Jun, 2019, 11:55: AM

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