CBSE Class 10 Answered
(1+secA)/secA = sin²A/(1-cosA)
Asked by nijurajeev7276 | 07 Jan, 2020, 10:27: AM
(1+secA)/secA = sin²A/(1-cosA)
![begin mathsize 16px style straight R. straight H. straight S equals space fraction numerator sin squared straight A over denominator 1 minus cosA end fraction equals space fraction numerator 1 minus cos squared straight A over denominator 1 minus cosA end fraction equals space fraction numerator open parentheses 1 minus cosA close parentheses open parentheses 1 plus cosA close parentheses over denominator open parentheses 1 minus cosA close parentheses end fraction equals 1 plus cosA equals space 1 plus 1 over secA equals fraction numerator 1 plus secA over denominator secA end fraction equals straight L. straight H. straight S
Hence space proved. end style](https://images.topperlearning.com/topper/tinymce/cache/1c51ec9b7c91d0ad0c79db5f045fb965.png)
Answered by Yasmeen Khan | 07 Jan, 2020, 11:12: AM
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