(1+secA)/secA = sin²A/(1-cosA)

 

Asked by nijurajeev7276 | 7th Jan, 2020, 10:27: AM

Expert Answer:

(1+secA)/secA = sin²A/(1-cosA)
begin mathsize 16px style straight R. straight H. straight S equals space fraction numerator sin squared straight A over denominator 1 minus cosA end fraction equals space fraction numerator 1 minus cos squared straight A over denominator 1 minus cosA end fraction equals space fraction numerator open parentheses 1 minus cosA close parentheses open parentheses 1 plus cosA close parentheses over denominator open parentheses 1 minus cosA close parentheses end fraction equals 1 plus cosA equals space 1 plus 1 over secA equals fraction numerator 1 plus secA over denominator secA end fraction equals straight L. straight H. straight S
Hence space proved. end style

Answered by Yasmeen Khan | 7th Jan, 2020, 11:12: AM