ICSE Class 9: Pythagoras Theorem Videos | Deriving Pythagoras Theorem from the concept of similar triangles
Deriving Pythagoras Theorem from the concept of similar triangles
Derive Pythagoras Theorem from the concept of similar triangles. Apply the same to solve problems.
More videos from this chapter
View All- prove by Pythagoras theorem that the diagonal of a rectangle are equal in length
-
Pythagoras Theorem
How to solve the problem in the given picture?
-
In triangle ABC, ∠B equals to 90° and D is midpoint of BC. Prove that AC 2 =AD 2 + 3 CD 2
- in tringle ABC, angle B is 90 °and D is the mid point of BC . prove that 1. AC² = AD² + 3CD² 2.BC²= 4(AD² -AB²)
- In rhombus ABCD , prove that : AB^2 + BC^2 + CD^2 + AD^2 = AD^2 + BD^2
- ABC is a right angled triangle in which ∠ABC = 90° and ∠ACB = 60°. BC is produced to D such that ∠ADB = 45°. If CD = 30 cm, what are the lengths of AB and BC?
- The sides of a right triangle containing the right angle are (5x) cm and (3x-1) cm. If the area of the triangle is 60 cm^2, calculate the length of the sides of the triangle.
- In an isoceles triangle ABC, AB=AC and D is a point BC produced. Prove that AD^2=AC^2 + BD * CD
- 1)A man travels 7 km due north ,then goes 3km due east and the 3 km due south.how far is he from starting point
- 1)The length of two sides of a right angled triangle containing the right angle differ by 6cm.If the area is 36cm2 find the perimeter 2) Solve simultaneously 3/x+4y=7 5/x+6y=13