ICSE Class 9 Maths Pythagoras Theorem
∆ABC is a right-angled triangle with ∠B = 90o. By Pythagoras theorem,
In ∆XYZ, XY2 = YZ2 + XZ2, so
∆ABC is a right-angled triangle with AB = 5 cm, AC = 3 cm and ∠C = 90o. Find BC.
In triangle ABC, ∠B equals to 90° and D is midpoint of BC. Prove that AC 2 =AD 2 + 3 CD 2
- in tringle ABC, angle B is 90 °and D is the mid point of BC . prove that 1. AC² = AD² + 3CD² 2.BC²= 4(AD² -AB²)
- In rhombus ABCD , prove that : AB^2 + BC^2 + CD^2 + AD^2 = AD^2 + BD^2
- ABC is a right angled triangle in which ∠ABC = 90° and ∠ACB = 60°. BC is produced to D such that ∠ADB = 45°. If CD = 30 cm, what are the lengths of AB and BC?
- The sides of a right triangle containing the right angle are (5x) cm and (3x-1) cm. If the area of the triangle is 60 cm^2, calculate the length of the sides of the triangle.
- In an isoceles triangle ABC, AB=AC and D is a point BC produced. Prove that AD^2=AC^2 + BD * CD
- 1)A man travels 7 km due north ,then goes 3km due east and the 3 km due south.how far is he from starting point
- 1)The length of two sides of a right angled triangle containing the right angle differ by 6cm.If the area is 36cm2 find the perimeter 2) Solve simultaneously 3/x+4y=7 5/x+6y=13
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