Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

URGENT

Asked by srprusty 16th March 2009, 10:38 PM
Answered by Expert
Answer:

Let the dimensions be l and b ( length and breadth).

Area=l*b

Perimeter=2(l+b)

Acc to qn,

 l*b=2(l+b)

b*(l-2)=2l

So,

b=2l/(l-2)

clearly if l and b are both zero, then rectangle doen' exist actually.

So next possible value for l must be >2

As the denominator has l-2, which must be positive.

Also, since lb=2(l+b),

 so clearly lb is an even number.

So both l and b can't be odd numbers.

by giving values to l, you can gt b

 and thus the dimensions.

Answered by Expert 16th March 2009, 11:10 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp