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Asked by pritam 6th April 2010, 10:28 PM
Answered by Expert
Answer:

u = -5 m

f = R/2 = +20/2 = 10 m

Therefore, 1/v + 1/u = 1/f

ie, 1/v = 1/f - 1/u

           = (1/10) - (1/-5)

           = (1/10) + (1/5)

           =  [(1+2)/10]

           = 3/10

thus, v = +10/3 m.

             = 3.333 m.

Magnification, h'/h = -v/u = -[10/(3x-5)] = +2/3

The image is formed betweent the pole and the focus.

Nature of the image is Virtual and Erect.

Image formed is diminished by a factor of 2/3.

Answered by Expert 8th April 2010, 10:48 AM
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