CBSE Class 12-science Answered
The electric field vector E1A at A due to the positive charge q1 points towards the right and has magnitude
The electric field vector E2A at A due to the negative charge q2 points towards the right and has the same magnitude.
The magnitude of the total electric field EA at A is:
EA is directed towards the right.
The electric field vector E1B at B due to the positive charge q1 points towards the left and has magnitude
The electric field vector E2B at B due to the positive charge q2 points towards the right and has magnitude
The magnitude of the total electric field EB at B is:
EB is directed towards the left.
The magnitude of each electric field vector at point C, due to charge q1 and q2 is:
The directions in which these two vectors point are shown in the figure.
The resultant of these two vectors is:
EC points towards the right.