CBSE Class 11-science Answered
Two motor cars start off with a gap of 2 min with the same acceleration how long after the departute of the second car does travel a distance equal to 1/9th of the distance covered by the first car.
Asked by contactpasala | 09 Jul, 2018, 08:23: PM
Expert Answer
Let t be time in seconds when the second car has travelled (1/9)th of distance travelled by first car as given in question.
There is a gap of 2 min or 120 s between the starting time of both the cars.
Distance travelled by first car, S1 = (1/2)×a×(120+t)2 .................(1)
Distance travelled by Second car, S2 = (1/2)×a×t2 ..................(2)
if S2 = (1/9)S1, then (1/18)×a×(120+t)2 = (1/2)×a×t2 ...........(3)
solving for t in eqn.(3), we get t = 60 s
Answered by Thiyagarajan K | 10 Jul, 2018, 09:25: PM
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