Two charge of 1 coulomb each are placed at a distance 9*10^-9m. Electric force between them will be

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Two charge of 1 coulomb each are placed at a distance 9*10^-9m. Electric force between them will be

Asked by bhuvanshetty1340 | 19 Apr, 2020, 07:42: PM

Expert Answer

By Coulomb's law,

F_c =( k q₁ q₂ )/ r²

k ≈ 9×10⁹ Nm² /C²

F_c = ( 9×10⁹ × 1 × 1) / ( 9 ×10^-9 )²

Thus, electric force between the two charges is,

F_c = 0.11 × 10⁹ N

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