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CBSE - X - Mathematics - Some Applications of Trigonometry

triangles

Asked by 13th February 2009, 10:25 PM
Answered by Expert

Answer:

A,B and C are the interior angles of a triangle.

So,

 A +  B+  C= 180

Now,

sin[( B+C)/2]=sin [(180-A)/2]

=sin[90-(A/2)]

=cos(A/2)

Answered by Expert 14th February 2009, 5:33 PM

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