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CBSE Class 12-science Answered

Three resistors 3ohm, 4ohm and 6ohm are connected in parallel. The combination is connected in series with a resistance of 1ohm and cell of emf 2V and internal resistance of 1ohm. Find the current through each resistor nd total current drawn from the cell!
Asked by shashankpkoila02 | 13 Feb, 2020, 04:39: PM
answered-by-expert Expert Answer
Left side figure shows the circuit that has parallel combination of 6Ω, 4Ω and 3Ω resistors connected in series to a 1Ω resistor.
This resistor combination is connected to a cell of emf 2V and internal resistance 1Ω.
 
Equivalenet resistance of 6Ω, 4Ω and 3Ω resistors =  (6×4×3)/ [ 6×4 + 4×3 + 3×6 ] = 4/3 Ω .
 
Replacement of parallel combination with 4/3 Ω is shown in right side figure.
 
Current in the circuit = 2V / [ (4/3)+1+1 ] Ω = 0.6 A
 
current through 1 Ω resistor = 0.6 A
 
Potential difference across the parallel resitors = current × equivalent Resistance = 0.6A × (4/3) Ω = 0.8 V
 
Hence current through 6Ω resistor = 0.8V/6Ω = 0.133 A
 
current through 4Ω resistor = 0.8V/4Ω = 0.2 A
 
current through 3Ω resistor = 0.8V/3Ω = 0.266 A
Answered by Thiyagarajan K | 13 Feb, 2020, 08:49: PM

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