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CBSE Class 11-science Answered

This question is spinning my head.. Please help..
Asked by nitishkrnehu09 | 23 Nov, 2017, 09:55: AM
answered-by-expert Expert Answer
begin mathsize 16px style According space to space the space given space condition space given space sequence space is space in space straight A. straight P. fraction numerator straight a subscript 1 plus straight a subscript 3 over denominator 2 end fraction equals straight a subscript 2...... left parenthesis straight i right parenthesis 2 straight a subscript 2 plus 2 straight a subscript 4 plus 2 straight a subscript 6 plus..... plus 2 straight a subscript 2012 equals 2 cross times 3018 2 straight a subscript 2 plus 2 straight a subscript 4 plus 2 straight a subscript 6 plus..... plus 2 straight a subscript 2012 equals 6036 From space left parenthesis straight i right parenthesis open parentheses straight a subscript 1 plus straight a subscript 3 close parentheses plus open parentheses straight a subscript 3 plus straight a subscript 5 close parentheses plus.... plus open parentheses straight a subscript 2011 plus straight a subscript 1 close parentheses equals 6036 2 straight a subscript 1 plus 2 straight a subscript 3 plus 2 straight a subscript 5 plus...... plus 2 straight a subscript 2011 equals 6036 2 open parentheses straight a subscript 1 plus straight a subscript 3 plus straight a subscript 5 plus...... plus straight a subscript 2011 close parentheses equals 6036 straight a subscript 1 plus straight a subscript 3 plus straight a subscript 5 plus...... plus straight a subscript 2011 equals 3018....... left parenthesis ii right parenthesis Adding space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis Sum space of space all space the space numbers space equals space 3018 plus 3018 equals 6036 end style
Answered by Sneha shidid | 29 Nov, 2017, 11:06: AM

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