NEET Class neet Answered
the passage of current liberates h2 at cathode and cl2 at anode . the solution is
Asked by sr8834055 | 20 Mar, 2024, 02:54: PM
Expert Answer
Dear Student,
The solution is sodium chloride in water.
As the discharge potential of water is greater than that of sodium water is reduced at the cathode instead of Na+1.
The reactions at the cathode and anode are as follows:
Cathode: H2O + e- → 1/2 H2 + OH-
Anode: Cl- → 1/2 Cl₂ + e-
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