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Asked by Prashant DIGHE | 22 Aug, 2020, 21:39: PM
Equation of electrolysis of dil. H2SO4 -
![At space Cathode minus
2 straight H to the power of plus space plus 2 straight e to the power of minus space rightwards arrow straight H subscript 2
At space Anode minus
2 OH to the power of minus rightwards arrow straight O subscript 2 plus 2 straight H subscript 2 straight O plus 4 straight e to the power of minus
Overall space reaction space would space be minus
straight H subscript 2 straight O rightwards arrow 2 straight H subscript 2 space end subscript plus straight O subscript 2
Amount space of space substance space at space cathode equals 2 space moles space of space straight H subscript 2 space equals 4 space straight g
Amount space of space substance space liberated space at space anode equals space 1 space mole space of space straight O subscript 2 space equals 32 space straight g
Ratio space of space substances space liberated space on space cathode space and space anode minus
4 colon 32
1 colon 8](https://images.topperlearning.com/topper/tinymce/cache/c4880bb4899b511d033470f1312fe76c.png)
Answered by Ravi | 23 Aug, 2020, 16:20: PM
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