CBSE Class 9 Answered
The graph given below is the distance - time graph of an object.
(i) Find the speed of the object during first four seconds of its journey. (ii) How long was it stationary?
(i) Find the speed of the object during first four seconds of its journey. (ii) How long was it stationary?
Asked by Topperlearning User | 15 Jun, 2016, 10:20: AM
Expert Answer
(i) The line OP, i.e. the first 4 seconds indicates uniform speed. Thus the speed of the object during this time interval will be the slope of line OP.
(ii) PQ is parallel to time axis, so speed is zero. Thus, the object is stationary between the time interval 14 s to 4 s.
Thus, the object is stationary for 14 - 4 = 10 s.
Answered by | 15 Jun, 2016, 12:20: PM
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