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The dissociation energy of H2 is 430.53 k J rnol-1 . If H2 is exposed to radiation energy of wavelength 253.7 nm, what % of radiant energy will be converted into kinetic energy?
Asked by eggwallet18 | 28 Apr, 2019, 09:29: PM
answered-by-expert Expert Answer
Given:
 
The dissociation energy of H2 = 430.53 kJ/mol
                                           = 430.53× 103 J/mol
Wavelength=253.7 nm
 
                 = 253.7 ×10-9 m
 
Planck's constant, h = 6.626×10−34 Jsec 
 
 
 
To break H-H bond energy reaquired is,
 
  space equals space fraction numerator 430.53 cross times 10 cubed over denominator 6.022 cross times 10 to the power of 23 end fraction space space equals space 71.49 space cross times 10 to the power of negative 20 end exponent space straight J
 
Energy of photon = 
 
hc over straight lambda space equals fraction numerator space 6.626 cross times 10 to the power of negative 34 space space end exponent cross times space 3 cross times 10 to the power of 8 over denominator 253.7 cross times 10 to the power of negative 9 end exponent end fraction space equals space 0.07835 space cross times 10 to the power of negative 17 end exponent space space equals 78.35 space cross times 10 to the power of negative 20 end exponent space straight J
 
Energy converted to kinetic energy =
 
 78.35 ×10−20 −   71.49 ×10−20 J
 

= 6.86 ×10−20 J
 
 
% of radiant energy converted into kinetic energy,
 
 equals space fraction numerator space 6.68 cross times 10 to the power of negative 20 space end exponent over denominator 78.35 end fraction cross times 100 space equals 8.75 percent sign
 
8.75% of radiant energy will be converted into kinetic energy.
Answered by Varsha | 29 Apr, 2019, 11:59: AM
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