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Asked by sarveshvibrantacademy | 29 Apr, 2019, 11:12: AM
Expert Answer
Let x cm is the object distance from lens. Let image is formed at other side of the lens at a distance v cm from lens.
Distance v is obtained from lens equation, (1/v) +(1/x) = 1/30 or v = 30x/(x-30) cm
Since mirror is placed at 15 cm from lens, image is formed at a distance (v-15) cm in front of reflecting surface of mirror.
Hence image distance from lens is (v-30) = [ 30x/(x-30) ]-30 = 900/(x-30) cm
Now this image is acting as object to form image at initial location
hence we have (1/x) + [ (x-30) /900 ] = 1/30 ...............(1)
By solving eqn.(1) for x, we get x = 30 cm
Answered by Thiyagarajan K | 29 Apr, 2019, 05:42: PM
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