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CBSE Class 11-science Answered

Solve log for (0.4×2)+(0.6×7)÷(0.4+0.6)
Asked by meyy962 | 06 Dec, 2020, 07:02: AM
answered-by-expert Expert Answer
Let X = ( 0.4 × 2 ) + ( 0.6 × 7 ) ÷ (0.4 + 0.6 )
 
Let X1 = ( 0.4 × 2 )
 
log( X1 ) = log (0.4 ) + log (2 ) = ( begin mathsize 14px style top enclose 1 end style .6021 + 0.3010 ) =  begin mathsize 14px style top enclose 1 end style.9031 
Hence X1 = Antilog(  begin mathsize 14px style top enclose 1 end style.9031 ) = 0.8
Let X2 = ( 0.6  × 7 )
 
log( X2 ) = log( 0.6 ) + log(7) = (  begin mathsize 14px style top enclose 1 end style.7782 + 0.8451 ) = 0.6232
X2 = Antilog ( 0.6232 ) = 4.2
 
Hence X = ( 0.8 + 4.2 ) ÷ (1.0) = 5
Answered by Thiyagarajan K | 06 Dec, 2020, 11:27: AM
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