CBSE Class 10 Answered
solve for alpha and beta
Asked by palaksophia | 26 Sep, 2009, 11:12: AM
Expert Answer
f(x) = ax2 + bx +c
The zeros are given by,
x = (- b ± 
(b2 - 4ac))/(2a)
Let @ = (- b + (b2 - 4ac))/(2a) and & = (- b - (b2 - 4ac))/(2a)
@ - & = (- b + (b2 - 4ac))/(2a) - (- b - (b2 - 4ac))/(2a)
= (b2 - 4ac)/a ...............................Answer
Generally the difference of the roots is, ±(b2 - 4ac)/a.
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Team,
TopperLearning.
Answered by | 26 Sep, 2009, 02:53: PM
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