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Asked by shobhitdc | 29th May, 2010, 10:52: AM

Expert Answer:

Dear Student,

As 1 is a zero of polynomial p(x) = ax2 - 3(a-1)x - 1

=> p(1) =0

=> a.12 - 3(a-1).1 - 1 = 0

=> a - 3a + 3 - 1 =0

=> -2a + 2 =0

=> -2a = -2

=> a = 1.

Regards Topperlearning.

Answered by  | 29th May, 2010, 11:34: AM

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