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Asked by shobhitdc | 29th May, 2010, 10:52: AM
Expert Answer:
Dear Student,
As 1 is a zero of polynomial p(x) = ax2 - 3(a-1)x - 1
=> p(1) =0
=> a.12 - 3(a-1).1 - 1 = 0
=> a - 3a + 3 - 1 =0
=> -2a + 2 =0
=> -2a = -2
=> a = 1.
Regards Topperlearning.
Answered by | 29th May, 2010, 11:34: AM
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