ans. please

Asked by shobhitdc | 29th May, 2010, 11:59: AM

Expert Answer:

The problem is not specified correctly, if the speed is increased the train would arrive BEFORE the scheduled time, and won't take 6 hrs more but less. Also the information is not sufficient.

Let the uniform speed be U and time required is T, then the distance is UT.

If (U + 6) then we had T - 6

but the distance would be same,

(U+6)(T-6) = UT

UT + 6T - 6U - 36 = UT

6T - 6U = 36

T - U = 6




Answered by  | 29th May, 2010, 07:22: PM

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