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CBSE Class 12-science Answered

Sir question attatched Question no. 10
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Asked by shobhit | 14 May, 2018, 08:54: AM
answered-by-expert Expert Answer
circumfrential displacement S of P as a function of time t is given by
 
S(t) = t2 + 5 ;
 
tangential speed of p ; (dS/dt) = v = 2t m/s
 
tangential acceleration of P ; (d2S/dt2) = at = 2 m/s2 ;
 
Radial acceleration of P  at   t = 5(√3/√10) ;  ar = v2/r = (4×25×3)/(10×20) = 1.5 m/s2
 
total acceleration a is given by
 
begin mathsize 12px style a space equals space square root of a subscript t superscript 2 plus a subscript r superscript 2 end root space equals space square root of 2 squared plus 1.5 squared end root space equals space 2.5 space m divided by s squared end style
Answered by Thiyagarajan K | 14 May, 2018, 03:03: PM

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