JEE Class main Answered
Question no 29
Asked by Adityaaryan681681 | 30 Jul, 2019, 10:15: PM
Expert Answer
Given:
Density = 1.15 g/L
P = 740 mm Hg
T = 300 K
Using ideal gas equation,
PV = nRT
Let % of N2 be X and O2 be (1-X)
Therefore,
28X + (1-X)32 = 29.09
28X + 32- 32X = 29.09
-4X = -2.90
X = 0.7274
=72.74 % of N2
Composition of N2 is 72%
Answered by Varsha | 31 Jul, 2019, 11:01: AM
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