CBSE Class 12-science Answered
Question is attached in image below. Please solve the question.
Asked by sumitshekhar891 | 10 Nov, 2019, 06:24: PM
Expert Answer
Parallel combination of R1 and RL is replaced by its equivalent resistance 1.2 kΩ in the left side figure
Current drawn from battery = 24 V / ( 2 + 1.2 ) kΩ = 7.5 mA
Voltage drop across R2 = 7.5 mA × 2 kΩ = 15 V.
Hence voltage drop across parallel combination of R1 and RL is 9 V
Hence only Statement-I is correct
Answered by Thiyagarajan K | 10 Nov, 2019, 07:46: PM
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