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CBSE Class 12-science Answered

Q - 7
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Asked by majethiyarishat9566.12sdatl | 21 Jun, 2020, 01:49: PM
answered-by-expert Expert Answer
Lets say there are n number of extra electrons present on the pith ball
Electric field generated by these electrons would be
E equals fraction numerator K n e over denominator r squared end fraction
1.3 cross times 10 cubed equals fraction numerator 9 cross times 10 to the power of 9 cross times n cross times 1.6 cross times 10 to the power of negative 19 end exponent over denominator open parentheses 0.1 close parentheses squared end fraction
n equals fraction numerator 1.3 cross times 10 cubed cross times open parentheses 0.1 close parentheses squared over denominator 9 cross times 10 to the power of 9 cross times 1.6 cross times 10 to the power of negative 19 end exponent end fraction
n equals 9.02 cross times 10 to the power of 9
Answered by Utkarsh Lokhande | 22 Jun, 2020, 02:54: PM
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