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# plzz tell me....................

Asked by 14th March 2009, 3:30 PM

Good to know that your exam went off well.

Here's the solution to your question.

Assume AB  to be the 8m tall building.with A as its top and B as its bottom.

Let EC be the multistoreyed building with E as its top and C as its bottom.

Mark D on EC such that DC=8 m(so ABCD is a rectangle)

Let BC=AD= x m and ED = h m

According to question,

angle EAD=30(alternate angle of the angle of depression)

and

angle EBC=45(same reason as above)

So,

x=hcot30..(i)

Next,

in triangle EBC,

tan45=(h+8)/x

So,

x=h+8..(ii)

Equating the value of x from both equations, we get,

h+8=h cot 30

h+8=h*(1.732)

8=h*(0.732)

h=8/0.732

calculate the final step and you will have the answer of h.

Add 8  to it and you will get the height of the multistoreyed building.

Answered by Expert 14th March 2009, 4:59 PM
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