CBSE Class 12-science Answered
plz explain
Asked by nagavalli72003 | 23 Apr, 2020, 02:28: AM
Expert Answer
By generalized ohm's law, J = σ E ...................(1)
where J is current density , σ is conductivity, E is electric field intensity.
Current through the spherical surface of radius r between the given concentrc metallic spheres is given by
I = Current density × Area = σ E × 4 π r2 ..................(2)
If conductivity σ of medium between concentric metallic spheres is given by, σ = kE .........(3)
Then by substituting for conductivity in eqn.(2), we get current I = 4πr2 kE2 ..................(4)
We get electric field E from eqn.(4) as
Potential V between concentric metallic spheres of radii b and a ( b > a ) is given by
Answered by Thiyagarajan K | 23 Apr, 2020, 05:39: PM
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