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CBSE - X - Mathematics - Some Applications of Trigonometry

plz answer soon tomorrow is exam plzzzzzzzzzzz

Asked by BhavSimran 10th March 2010, 12:05 PM
Answered by Expert

Answer:

let angle C be acute, or obtuse.

draw AD perpendicuar to BC(or BC produced if necessary)

Now,

cosC =CD/CA

So

CD=CA cosC

let a=BC

b=CA

c=AB

then we get,

from this we can get the required result.

 note that going along  similar lines we can prove the result even if C is an obtuse angle.

Answered by Expert 10th March 2010, 3:50 PM

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