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CBSE Class 12-science Answered

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Asked by dakshitak2002 | 24 Apr, 2020, 07:22: PM
answered-by-expert Expert Answer
Distances from point P to charges are marked in the figure .
 
Potential V at point p due to point charges is given by,
 
begin mathsize 14px style V space equals space open curly brackets fraction numerator 2 square root of 2 space q over denominator a end fraction space plus space fraction numerator square root of 2 space q over denominator a end fraction space minus space fraction numerator square root of 2 space q over denominator a end fraction close curly brackets fraction numerator 1 over denominator 4 pi epsilon subscript o end fraction space equals space fraction numerator 2 square root of 2 q over denominator open parentheses 4 pi epsilon subscript o close parentheses a end fraction end style
------------------------------------------------
 
To determine the potential energy of configuration, let us assume intially we had +2q charge at origin .
 
Workdone W1 to bring +q charge upto (0, a) from infinity is given by
 
W1 = 2 q2 / [ (4πεo) a ]
 
Workdone W2 to bring +q charge upto (a, 0) from infinity when charges are alreay there at origin and at a point (0,a)
is given by
 
W2 = - 2 q2 / [ (4πεo) a ]  -  q2 / [ (4πεo) √2 a ] 
 
Total workdone , i.e., potential energy of configuration,  W1 + W2 = - q2 / [ (4πεo) √2 a ]
 
-ve sign indicates work is done by field
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Answered by Thiyagarajan K | 24 Apr, 2020, 09:47: PM

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