CBSE Class 12-science Answered
pls explain the answer
Asked by mufeedatvp2000 | 17 Apr, 2020, 07:34: PM
Expert Answer
Measured time for 20 oscillation = 25±0.2 s
Time for 1 oscillation = ( 25 ± 0.2 ) /20 = 1.25 ± 0.01
percentage error = (0.01/1.25)×100 = 100/125 = 0.8%
Answered by Thiyagarajan K | 17 Apr, 2020, 08:28: PM
Concept Videos
CBSE 12-science - Physics
Asked by ankush76728 | 06 May, 2024, 04:52: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by ankush76728 | 05 May, 2024, 09:55: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by heymindurownbusiness | 04 May, 2024, 11:15: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by talulu | 01 May, 2024, 05:14: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by kanishkg511 | 30 Apr, 2024, 07:25: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by sahoobanita89 | 30 Apr, 2024, 05:10: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by divakar.9124 | 27 Apr, 2024, 10:42: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by panneer1766 | 24 Apr, 2024, 01:52: PM
ANSWERED BY EXPERT