Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

please

qsnImg
Asked by arup.isro 25th June 2019, 11:26 PM
Answered by Expert
Answer:
Figure shows the capacitor plates with dielectric placed at centre as given in question.
Electric field vectors at air and in dielectric are shown in figure. Potential is also plotted and shown in figure.
 
(A) As one goes from x=0 to x=3d, Magnitude of electric field remains same .
This is incorrect statement. Electric field in air space is greater than the electric field inside dielectric.
This is due to induced charges inside dielectric which are reversed in comparision with charges of capacitor plates.
 
(B) As one goes from x=0 to x=3d, Direction of electric field same
This is correct statement. Only magnitude of electric field is decreased inside dielectric but direction of net field is same.
 
(C) As one goes from x=0 to x=3d, potential increases continuously
This is incorect statement. Figure shows the potential plot as a function of distance from plate which is at x = 0.
 
(D) As one goes from x=0 to x=3d, potential increases at first, then decreases and again increases.
This is corect statement as seen from the potential plot as a function of distance
Answered by Expert 26th June 2019, 5:51 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp