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Please solve the problem in the image.Provide the steps.
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Asked by miaowmira1900 | 11 Aug, 2019, 02:26: PM
answered-by-expert Expert Answer
if Vx is 1.9 V  and vx is 4 mV means, a small ac signal  vx is super imposed in  the DC voltage Vx .
 
Hence Vx varies between 1.402 V and 1.398 V
 
when Vx = 1.402 V, current iD = -28×10-3 (1.402 - 0.9 )  = 14.056 mA
when Vx = 1.398 V, current iD = -28×10-3 (1.398 - 0.9 )  = 13.944 mA
 
hence ac current id = (14.056 - 13.944) mA = 0.112 mA = 112 μA
Answered by Thiyagarajan K | 11 Aug, 2019, 04:52: PM
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