CBSE Class 12-science Answered
Please solve it .
Asked by abhitailor158 | 14 Apr, 2020, 06:49: PM
Expert Answer
Flux density for primary turns when secondary is unloaded is calculated from the following relatio
E = 4.44 × N × B × A × f ...................(1)
where E RMS value of applied voltage, N is number of turns, B is flux density of magnetic field,
A is area of cross section and f is frequency of applied voltage.
Magnetic flux φ = B × A
we get Magnetic flux from eqn.(1) as , φ = B × A = E / (4.44 × N × f )
Magnetic flux φ = 230 / ( 4.44 × 200 × 50 ) = 5.18 × 10-3 Wb
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Input power to primary = 230×5 = 1150 W
power factor = 0.25
Core Loss = Power input to primary × power factor = 1150 × 0.25 = 287.5 W
------------------------------------------------
Magnetizing current = Power disspated in Core / primary Voltage = 287.5/230 = 1.25 A
Answered by Thiyagarajan K | 14 Apr, 2020, 08:35: PM
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