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please solve

Asked by gober45 13th February 2009, 5:28 PM
Answered by Expert
Answer:

l tan θ + m sec θ = n .....(1)     l' tan θ - m' sec θ = n'........(2)

mltiply 1 with m'  and 2 with m and add we get sec θ term cancelled out and tan θ = (nm' + mn') / (lm' + ml')

similaly multiply 1 with l' and 2 with l and subtract tan θ cancelled out and we have sec θ =  (nl' - ln') / (ml' + lm')

we knoe 1 + tan 2 θ = sec 2 θ  so put the value get the answer

Answered by Expert 13th February 2009, 7:20 PM
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