NEET Class neet Answered

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Asked by Balbir | 01 Oct, 2019, 11:40: PM

Expert Answer

For the cell,

Cd space space left enclose space Cd left parenthesis OH right parenthesis subscript 2 space end enclose left enclose space NaOH left parenthesis 0.01 straight M right parenthesis space space left enclose space straight H subscript 2 space left parenthesis 1 atm right parenthesis space space left enclose space Pt end enclose end enclose end enclose At space anode space space space space space space space space space space space space space space space space space space space space space space space space space space space space space Cd space rightwards arrow with blank on top space Cd to the power of plus 2 end exponent space space plus space space 2 straight e to the power of minus at space cathode space space space space space space 2 straight H to the power of plus space space plus space space 2 straight e to the power of minus space rightwards arrow with blank on top space space straight H subscript 2 space space straight E subscript cell space end subscript space equals space space straight E subscript cell superscript 0 space plus fraction numerator 0.0591 over denominator straight n end fraction log fraction numerator left square bracket straight H to the power of plus right square bracket squared over denominator left square bracket Cd to the power of plus 2 end exponent right square bracket end fraction space straight E subscript cell space space equals space straight E subscript cell superscript 0 space plus fraction numerator 0.0591 over denominator straight n end fraction log fraction numerator space space left square bracket straight H to the power of plus right square bracket to the power of 2 space space space end exponent left square bracket OH to the power of minus right square bracket squared over denominator left square bracket Cd to the power of plus 2 end exponent right square bracket space space space space left square bracket OH to the power of minus right square bracket squared end fraction space 0.0 space space space equals space left square bracket 0 minus left parenthesis negative 0.40 right parenthesis right square bracket space plus fraction numerator 0.0591 over denominator straight n end fraction log fraction numerator straight K subscript straight w superscript 2 over denominator straight K subscript sp end fraction equals space 0.40 space plus space 0.0295 space space log space fraction numerator straight K subscript straight w superscript 2 over denominator straight K subscript sp end fraction log fraction numerator straight K subscript sp over denominator straight K subscript straight w superscript 2 end fraction equals fraction numerator 0.40 over denominator 0.0295 end fraction space equals space 13.559 Take space antilog comma fraction numerator straight K subscript sp over denominator straight K subscript straight w superscript 2 end fraction equals space space antilog space open parentheses 13.559 close parentheses fraction numerator straight K subscript sp over denominator straight K subscript straight w superscript 2 end fraction equals 3.62 space cross times 10 to the power of 13 straight K subscript sp space equals space 3.62 space cross times 10 to the power of 13 space cross times 10 to the power of negative 28 end exponent space equals space 3.62 space cross times 10 to the power of negative 15 end exponent

Answered by Ramandeep | 15 Oct, 2019, 11:19: AM

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