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CBSE Class 11-science Answered

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Asked by Prashant DIGHE | 29 Feb, 2020, 09:50: PM
answered-by-expert Expert Answer
Let the formula of unknown carbonate=XCO3
M o l e c u l a r space w e i g h t space o f space X C O 3 space equals left parenthesis x plus 12 plus 48 right parenthesis g equals left parenthesis 60 plus x right parenthesis g
x space i s space t h e space a t o m i c space m a s s space of space element space space straight X
percent sign space composition space of space carbon equals left square bracket 12 divided by left parenthesis 60 plus straight x right parenthesis right square bracket cross times 100
6.091 equals left square bracket 12 divided by left parenthesis 60 plus straight x right parenthesis right square bracket cross times 10060 plus straight x
0.0691 equals left square bracket 12 divided by 60 plus straight x right square bracket
0.0691 left parenthesis 60 plus straight x right parenthesis equals 12
3.6546 space plus space 0.06091 straight x equals 126091 straight x
0.06091 straight x equals 8.3454
straight x equals 137.01
Answered by Ravi | 01 Mar, 2020, 10:17: PM
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