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CBSE Class 11-science Answered

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Asked by Prashant DIGHE | 06 Jan, 2020, 09:58: PM
answered-by-expert Expert Answer

The chemical equation of the reaction is:  

   HCl  +  AgNO3   →    AgCl  +  HNO3
 
begin mathsize 11px style Amount space of space HCl space mg space required space to space produce space 0.1435 space straight g space AgCl space equals space fraction numerator 36.5 over denominator 143.5 end fraction space cross times space 0.1435 space equals space 0.0365 space straight g Thus space 10.0 space ml space HCl space contains space HCl space equals space 0.0365 space straight g space equals space fraction numerator 0.0365 over denominator 36.5 end fraction space equals space 10 to the power of negative 3 end exponent space moles Hence comma space molarity space of space HCl space equals space 10 to the power of negative 3 end exponent over 10 space cross times space 1000 space equals space 0.1 space straight M end style

 In case of HCl ,

Molarity=Normality 

So Normality=0.1 M

Answered by Ravi | 07 Jan, 2020, 12:14: PM
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CBSE 11-science - Chemistry
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Asked by brijk456 | 22 Aug, 2019, 11:00: AM
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CBSE 11-science - Chemistry
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