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please answer

Asked by pranavjain 1st May 2010, 4:54 PM
Answered by Expert
Answer:

let the number be x.

ATQ

when x is divided by 35 it leaves a rem of 7

i.e.

x-7 is fully divisible by 35

i.e.

x-7 is a multiple of 35

similarly

x-7 is a multiple of 56 and 91.

so we see that

x-7 is a common multiple of 35,56,91

since we want the smallest num so x-7 is the least common multiple of  35,56,91

so x-7=3640(since 3640 is the reqd l c m )

so

x=3647

Answered by Expert 4th May 2010, 4:44 PM
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