CBSE Class 12-science Answered
please answer
Asked by arup.isro | 25 Jun, 2019, 11:26: PM
Expert Answer
Potential difference Vt at time t across capacitor of capacitance C discharging throuh resistance R , Vt = V0 e-t/RC .........(1)
where V0 is initial voltage across capacitor
Potential difference after 1 sec, V1 = V0 e-1/RC or 40 = 50 e-1/RC .........................(2)
Potential difference after 2 sec, V2 = V0 e-2/RC or V2 = 50 e-2/RC .........................(3)
using eqn.(3), we rewrite eqn.(3) as , V2 = 50×(40/50)×(40/50) = 32 V ...........................(4)
Energy stored in capacitor = (1/2) C V2 ...................(5)
as seen from eqn.(5), Energy stored in a given capacitor is directly proportional to Voltage across the capacitor plates.
Hence fraction of energy stored after 1 second = (40×40) / (50×50) = 16/25
Hence only statements (A) and (B) are correct .
Answered by Thiyagarajan K | 26 Jun, 2019, 01:07: PM
Concept Videos
CBSE 12-science - Physics
Asked by panneer1766 | 24 Apr, 2024, 01:52: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by artabandhusahu85 | 24 Apr, 2024, 12:07: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by niharvijayvargiya5 | 23 Apr, 2024, 06:40: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by kulhariabhijeet | 21 Apr, 2024, 02:39: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by mohapatraswetalina88 | 21 Apr, 2024, 12:18: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by aishaisha091098 | 19 Apr, 2024, 04:54: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by dasrituparna1999 | 13 Apr, 2024, 06:56: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by dasrituparna1999 | 12 Apr, 2024, 09:26: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by mishrigupta19319 | 08 Apr, 2024, 06:28: PM
ANSWERED BY EXPERT