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CBSE Class 11-science Answered

Object length u=50±0.2cm Image length v=80±0.2cm Find focal length.
Asked by simasarkar1968 | 26 May, 2020, 12:35: PM
answered-by-expert Expert Answer
A s s u m i n g space t h e s e space d i m e n s i o n s space f o r space t h e space l e n s
1 over v minus 1 over u equals 1 over f
1 over 80 minus fraction numerator 1 over denominator negative 50 end fraction equals 1 over f
fraction numerator 5 plus 8 over denominator 400 end fraction equals 1 over f
f equals 400 over 13
M a x i m u m space e r r o r
fraction numerator increment f over denominator f squared end fraction equals fraction numerator increment u over denominator u squared end fraction plus fraction numerator increment v over denominator v squared end fraction
fraction numerator increment f over denominator open parentheses begin display style 400 over 13 end style close parentheses squared end fraction equals fraction numerator 0.2 over denominator 50 squared end fraction plus fraction numerator 0.2 over denominator 80 squared end fraction
O n space s o l v i n g space t h e space t o t a l space f o c a l space l e n g t h space c i s
f plus increment f.
Answered by Utkarsh Lokhande | 26 May, 2020, 08:29: PM
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