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CBSE Class 12-science Answered

In a series LCR circuit, VL = VC ≠ VR. What is the value of power factor? 
Asked by Topperlearning User | 08 Jul, 2015, 11:23: AM
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Answered by | 08 Jul, 2015, 01:23: PM

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CBSE 12-science - Physics
tan Phi = XL-XC/R, what is Tan Phi called here
Asked by sky11841 | 08 Sep, 2021, 10:04: PM
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CBSE 12-science - Physics
What is reactance and susceptance?
Asked by Topperlearning User | 22 Jun, 2015, 09:59: AM
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CBSE 12-science - Physics
What is impedance?
Asked by Topperlearning User | 22 Jun, 2015, 10:02: AM
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CBSE 12-science - Physics
In a RLC circuit R = 10 Ω , L = 0.1 H , XC = 12 Ω are joined across 200 V 50 Hz a.c. supply. Calculate its impedance.
Asked by Topperlearning User | 22 Jun, 2015, 10:10: AM
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CBSE 12-science - Physics
Find the phase angle for RLC circuit with XC = 14 and XL = 30 and R = 10
Asked by Topperlearning User | 22 Jun, 2015, 10:12: AM
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CBSE 12-science - Physics
In a circuit a coil of resistance 100 Ω and inductance 0.1 H are connected across an ac voltage of frequency 100/2π Hz. What is the phase difference?
Asked by Topperlearning User | 22 Jun, 2015, 10:15: AM
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CBSE 12-science - Physics
Find the series resonance frequency for a circuit when L = 0.1 H and C = 10 F.
Asked by Topperlearning User | 22 Jun, 2015, 10:18: AM
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CBSE 12-science - Physics
What is Q factor of series resonant circuit and what will happen to the Q factor if the resistance increases?
Asked by Topperlearning User | 22 Jun, 2015, 10:23: AM
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CBSE 12-science - Physics
A resistor of 12 Ω and inductance 2 H are connected in series to a 220 V, 50 Hz a.c. source. Find the total impedance of LR circuit.
Asked by Topperlearning User | 22 Jun, 2015, 10:35: AM
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CBSE 12-science - Physics
a resistor of 30 Ω and a capacitor of 0.25 μF are connected in series to a 100 V source (ω=10,000 rad/sec). Find the current in the circuit and the rms voltage across the resistor and the capacitor. Is the algebraic sum of these voltages more than the source voltage? If yes, resolve the paradox.
Asked by Topperlearning User | 22 Jun, 2015, 11:20: AM
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