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In a game, a man wins a rupee for a six and loses a rupee for any other number when a fair die is thrown. The man decided to throw a die thrice but to quit as and when he gets a six. Find the expected value of the amount he wins/loses. If he does not get a six in the first throw and gets a six in the second throw, then probability = Amount he will receive = ?Re 1 + Re 1 = 0

Asked by prabhakar p 17th March 2013, 6:15 PM
We need to consider the fourth case even where he does not get a 6 in any of his throws.

Please note the answer in the book is wrong as that can be derived only by not considering this 4th case.
Answered by Expert 17th March 2013, 6:46 PM
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