Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

How to calculate moment of inertia in these type of problems explain please
question image
Asked by nipunverma59 | 05 Apr, 2019, 01:10: PM
answered-by-expert Expert Answer
In case-1, all spheres are 25 cm from axis of rotation.
 
By parallel axis theorem, moment of inertia of sphere whose axis of rotation is parallel to axis of sphere = (2/5)MR2 +Md2  .....(1)
 
where M is mass of sphere, R is radius of sphere and d is distance between axis of rotation and axis of sphere.
 
Using eqn.(1), Moment of Inertia I1 of 4 solid spheres for case-1 = 4×[ (2/5)×1×102 ×10-4 + 1×252×10-4 ] = 0.266 kgm2 ............(2)
 
In case-2 two spheres are in axis of roattion and other two spheres are 25√2 cm away from axis of rotation.
 
Hence moment of inertia I2 for case-2  = 2×[ (2/5)×1×102×10-4 ] + 2×[ (2/5)×1×102×10-4 + 1×(25√2)2×10-4 ] = 0.266 kgm2 ..........(3)
 
from (2) and (3), we have  I1 = I2  or  begin mathsize 12px style I subscript 1 over I subscript 2 space equals space 1 end style
Answered by Thiyagarajan K | 05 Apr, 2019, 04:09: PM

Application Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
JEE main - Physics
explain it clearly
question image
Asked by ravichandraravula66 | 29 Apr, 2024, 11:20: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Alternating Current
question image
Asked by kmani310507 | 28 Apr, 2024, 04:38: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
find current
question image
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Three equal charges, 2⋅0 × 10 − 6 C each, are held fixed at the three corners of an equilateral triangle of side 5 cm. Find the Coulomb force experienced by one of the charges due to the rest two.
question image
Asked by ratnadeep.dmr003 | 21 Apr, 2024, 11:06: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Time period for a simple harmonic motion (d ^ 2 * x)/(d * t ^ 2) =- mu xis:
Asked by ksahu8511 | 19 Apr, 2024, 11:55: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
find the acceleration
question image
Asked by mohammedimroz | 13 Apr, 2024, 09:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
solution of 12th question
question image
Asked by medhamahesh007 | 02 Apr, 2024, 11:11: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
if Bi with a mass number 211 and atomic number 83 undergoes beta decay the resultant daughter nuclei will be
Asked by gundlasumathi93 | 31 Mar, 2024, 02:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
four charges are arranged at corners of square abcd as in figur the force on charge kept at centre o is
question image
Asked by chhayasharma9494 | 31 Mar, 2024, 12:47: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
two small conducting spheres each of mass 9×10‐⁴kg qre suspended from the same point by non conducting strings of length 100cm. they are given equal and similar charges until the strings are rqually inclined at 45° each to the vertcal. The charge on each sphere is
Asked by archithateja3 | 30 Mar, 2024, 10:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×