CBSE Class 12-science Answered
Hiii
Asked by jain.pradeep | 24 Apr, 2019, 01:45: AM
Expert Answer
Qn.42 - Cooling curve reaches a near constant vlaue 20°C and the rate of decrease is negligibly small.
Hence room temperature is near to 20°C
Qn.43 - From initial temperature 60°C to the temperature 34°C, time duration is 3/2 hour as per cooling curve.
Hence loss of energy per hour = ( 8×105×26 ) / (3/2) = 13.86×106 J
Answered by Thiyagarajan K | 24 Apr, 2019, 12:51: PM
Concept Videos
-
Electric Charge - Part 1
This video describes the concept of charge, conductors and insulators, and ... -
Gold Leaf Electroscope - Part 1
This video explains the basic properties of electric charges. -
Coulom's Law of Electric Force - Part 1 ...
This video describes Coulomb's law to calculate the force between any two p... -
All about electric fields
Define electric field in terms of Coulomb's force. Apply superposition prin... -
Electric Field Lines
This video explains the representation of electric field due to a single ch...
CBSE 12-science - Physics
Asked by ankush76728 | 06 May, 2024, 04:52: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by ankush76728 | 05 May, 2024, 09:55: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by heymindurownbusiness | 04 May, 2024, 11:15: AM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by talulu | 01 May, 2024, 05:14: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by kanishkg511 | 30 Apr, 2024, 07:25: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by sahoobanita89 | 30 Apr, 2024, 05:10: AM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by divakar.9124 | 27 Apr, 2024, 10:42: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by panneer1766 | 24 Apr, 2024, 01:52: PM
ANSWERED BY EXPERT
