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# Hi

(3) distance S from starting point of an object moving with constant positive acceleration a

S = (1/2)at

If a = 2 unite, then S = t2 .................. (1)

Numbers in set-C matching this eqn.(1)
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(4) Speed of an object acted upon by a constant force opposite in direction to its velocity.
v = u - (f/m)×t .................(2)
where v is speed at instant of time t , u is initial speed, f is force and m is mass so that f/m gives acceleration.

Numbers in set-D matching the equation, with u = 12 unit,  f/m = 2 unit

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(5) kinetic energy of block moving downwards in a inclined plane and moving under the influence of gravity.

If the block is released from top of inclined plane, its speed v at time t is given by,

v = g sinθ×t

hence kinetic energy (1/2)mv2 = (1/2)m×( g2 sin2θ)×t2   or kinetic energy = K×t2  ........................(3)
where K  is constant.

Numbers in set-C are matching to the second degree equation (3) , with K =1
Answered by Expert 25th May 2019, 11:13 PM
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