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CBSE Class 11-science Answered

give the answer of question in image plz??
question image
Asked by harshyadav4758 | 28 Mar, 2020, 10:31: AM
answered-by-expert Expert Answer
Molecular mass of FeSO4.7H2O =277.8
p p m equals fraction numerator W t. space o f space F e over denominator W t. space o f space end fraction cross times 10 to the power of 6
L e t space t h e space w t space o f space s a l t space b e space equals w space g m
m o l e s equals fraction numerator w over denominator 277.85 end fraction
W t. space o f space F e equals left parenthesis fraction numerator W over denominator 277.85 end fraction cross times 55.85 right parenthesis space g m
10 equals fraction numerator begin display style fraction numerator w over denominator 277.85 end fraction end style cross times 55.85 over denominator 10 to the power of 5 end fraction cross times 10 to the power of 6
W equals fraction numerator 277.85 over denominator 55.85 end fraction equals 4.97
Answered by Ravi | 28 Mar, 2020, 09:03: PM
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