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Find three terms in AP such that their sum is 3 and product is -8.

Asked by Topperlearning User 20th November 2013, 12:20 AM
Answered by Expert
Answer:

Let a - d, a and a + d be three terms in AP.

According to the question,

a - d + a + a + d = 3

3a = 3 or a = 1

(a - d) (a) (a + d) = -8

a(a2 - d2) = -8

Putting the value of a = 1, we get,

1 - d2 = -8

d2 = 9 or d = ±3

Thus, the required three terms are -2, 1, 4 or 4,1,-2.

Answered by Expert 20th November 2013, 2:20 AM
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