Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Home / Doubts and Solutions/CBSE/Class 10/Mathematics

Find three terms in AP such that their sum is 3 and product is -8.

Asked by Topperlearning User 20th November 2013, 12:20 AM
Answered by Expert
Answer:

Let a - d, a and a + d be three terms in AP.

According to the question,

a - d + a + a + d = 3

3a = 3 or a = 1

(a - d) (a) (a + d) = -8

a(a2 - d2) = -8

Putting the value of a = 1, we get,

1 - d2 = -8

d2 = 9 or d = ±3

Thus, the required three terms are -2, 1, 4 or 4,1,-2.

Answered by Expert 20th November 2013, 2:20 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

Q1) if alpha and beta are zeroes of the quadratic polynomial f(x)=3x²-5x-2, then evaluate alpha³+beta³
Q2) if one of the zeroes of the cubic polynomial x³+ax²+bx-c is -1, then find the product of other two zeroes? (Plz help because its answer us given c of Q2)
13th June 2016, 9:35 AM
Write cubic polynomial whose zeroes are 2+√5/2, 2-√5/2 and 4
13th June 2016, 9:45 AM

if x,y are two positive odd integers thenx2+y2 _____

answer given in test odd,is it right ? if yes then please tell me how.

thanks

13th June 2016, 9:49 AM
What are coprime numbers? Explain.
13th June 2016, 10:35 AM
How we will split the middle term of this
3x^2 - 2x - 8 ?
Explain also.
13th June 2016, 10:41 AM
RELATED STUDY RESOURCES :
CBSE Class-10 QUESTION ANSWERS

Chat with us on WhatsApp