Find three terms in AP such that their sum is 3 and product is -8.
Asked by Topperlearning User
20th November 2013,
12:20 AM
Answered by Expert
Answer:
Let a - d, a and a + d be three terms in AP.
According to the question,
a - d + a + a + d = 3
3a = 3 or a = 1
(a - d) (a) (a + d) = -8
a(a2 - d2) = -8
Putting the value of a = 1, we get,
1 - d2 = -8
d2 = 9 or d = ±3
Thus, the required three terms are -2, 1, 4 or 4,1,-2.
Answered by Expert
20th November 2013,
2:20 AM
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