CBSE Class 10 Answered
Expert Answer
Let Sn = 6+13+20+..................+97
Above series is Arithmetic progression with first term a = 6 and common difference d = 7
Last term 97 is
6 + (n-1)7 = 97
From above expression, n = 14 .
Hence number of terms n in the arithmetic progression is 14.
Sum of Arithmetic progression is
Sn = (14/2) [ 2 × 6 + 13 × 7 ] = 721
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