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CBSE Class 10 Answered

Find the value of p, for which one root of the quadratic equation px2-14x+8=0 is 6 times the other  
Asked by sampark2sanjay | 23 Jan, 2018, 09:55: AM
answered-by-expert Expert Answer
begin mathsize 16px style Given space quadratic space equation equals px squared minus 14 straight x plus 8 equals 0 Here comma space straight a equals straight p comma space straight b equals negative 14 comma space straight c equals 8 Let space one space root space of space the space given space equation space be space straight alpha. rightwards double arrow Other space root equals 6 straight alpha Now comma space sum space of space the space roots equals negative straight b over straight a rightwards double arrow straight alpha plus 6 straight alpha equals negative fraction numerator left parenthesis negative 14 right parenthesis over denominator straight p end fraction Solving comma space straight p equals 2 over straight alpha Product space of space roots equals straight c over straight a rightwards double arrow straight alpha cross times 6 straight alpha equals 8 over straight p rightwards double arrow straight p equals fraction numerator 4 over denominator 3 straight alpha squared end fraction rightwards double arrow fraction numerator 4 over denominator 3 straight alpha squared end fraction equals 2 over straight alpha rightwards double arrow straight alpha equals 2 over 3 rightwards double arrow straight p equals 3 end style
Answered by Rashmi Khot | 24 Jan, 2018, 10:12: AM

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